Степени и корни

an =

aaa ⋅ ... ⋅ aaa


n раз

aR, bR, b ≠ 0, mZ, nZ

1) a0 = 1

2) a1 = a

3) 1n = 1

4) anam = an + m

5) an am = an-m

6) (ab)n = anbn

7) ( a b ) n = an bn

8) (an)m = anm

9) a-n= 1 an

10) ( a b ) -n = ( b a ) n

1) ann=a

2) a n m = an m

3) ( a m ) n = an m

4) a m n = a nm

5) akm kn = an m

6) ab n = a n b n

7) a b n = an bn

8) am bn= anbmmn

Решение показательных неравенств:

f(x)g1(x)f(x)g2(x) > 0

(f(x) − 1)(g1(x)g2(x)) > 0

Вверх